| Display title | Monty Hall Problem |
| Default sort key | Monty Hall Problem |
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| Page ID | 136136 |
| Page content language | en - English |
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| Page creator | m>Import Bot |
| Date of page creation | 21:27, 1 November 2013 |
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| Date of latest edit | 09:02, 9 April 2017 |
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Description | Content |
Article description: (description)
This attribute controls the content of the description and og:description elements. | A classic mathematical problem involving probabilites. The basic form is based on one of the games on the Game Show Let's Make a Deal. The contestant is offered the choice of three doors. One has a car behind it, the two others hide goats. The contestant chooses a door. The host (who knows what is behind each door) then opens one of the two other doors, revealing a goat. The contestant is then offered the choice to switch to the unrevealed door or stick with his original decision. The correct answer is to switch, as the probability is 66.7% that the car will be behind the other door. This is because there was a 2 in 3 chance that you chose a goat originally, and the host isn't providing any new information since he can always open a door with a goat. See The Other Wiki for an explanation of the math. Note that this number is true only if the host is required to reveal a goat and then offer the contestant the choice to switch. See The New York Times for what happens when the host is not. |